Write a program to get the nth byte of an integer

Problem statement: Given an integer, write a program to extract the nth byte from it.

Example: Let's take an integer in hexadecimal format, say 0x5510EF3A (a 32-bit integer). It has four bytes, given in hexadecimal as:
     Byte 0: 0x3A
     Byte 1: 0xEF
     Byte 2: 0x10
     Byte 3: 0x55
So, if we want to get byte #2, the result would be 0x10.

Solution: We can move the required byte to the rightmost position by right-shifting the number by (8 * required byte number). Now we only need the rightmost byte in our result (the last 8 bits), so we can mask it by doing bitwise AND with 0x000000FF, which is also written as just 0xFF, or 255 in decimal.

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#include <stdio.h>   int getByte(int num, unsigned byteno) {     return (num >> (byteno * 8)) & 0xFF;    // Mask and return the required byte }   int main() {     int num;     unsigned byteno;       printf("\nEnter a hex number: ");     scanf("%x", &num);        // To take input number in hex, by using %x     printf("\nEnter byte no to get (0 - 3): ");     scanf("%u", &byteno);     // To take byte no in unsigned decimal, by using %u       printf("\nByte no %u in hex representation: %x\n", byteno, getByte(num, byteno));       return 0; }